document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64554>Question 64554</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line through (-1,2) that is perpendicular to 3x-y=4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45167 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45167\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x-y=4<BR>\n" );
document.write( "-y=-3x+4<BR>\n" );
document.write( "y=3x-4 thus the slope of this line is 3. A line perpendicular to this one has a slope of -1/3. Using this slope & the two points we have the line formula of--<BR>\n" );
document.write( "y=mx+b where m=slope & b=y intercept.<BR>\n" );
document.write( "2=(-1/3)*-1+b<BR>\n" );
document.write( "2=1/3+b<BR>\n" );
document.write( "b=2-1/3<BR>\n" );
document.write( "b=1 2/3 or 5/3<BR>\n" );
document.write( "Thus this line is y=-1/3x+5/3  <BR>\n" );
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