document.write( "Question 740686: 1. Four students are running for class president. How many different ways can they be listed on the ballot?
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Algebra.Com's Answer #451663 by Ed Parker(21)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "There are 4 ways to pick a candidate to be first on the list.\r\n" ); document.write( "\r\n" ); document.write( "For every one of those 4 ways to pick a candidate to be in first place, there\r\n" ); document.write( "are only 3 ways left to pick one to be in second place, so there are 4 times 3\r\n" ); document.write( "or 12 ways to pick 2 candidates to be in first and second place on the list.\r\n" ); document.write( "\r\n" ); document.write( "For every one of those 12 ways to pick two candidates to be in first and second\r\n" ); document.write( "place, there are only 2 ways left to pick one to be in third place, so there\r\n" ); document.write( "are 12 times 2 or 24 ways to pick 3 candidates to be in first, second and third\r\n" ); document.write( "places on the list.\r\n" ); document.write( "\r\n" ); document.write( "Now there is only 1 candidate left to pick to be last. So that's just 1 way.\r\n" ); document.write( "\r\n" ); document.write( "So multiplying 24 by 1 still leaves it at 24, because when you pick all but 1,\r\n" ); document.write( "you have automatically picked the only remaining candidate's popsition because\r\n" ); document.write( "the one remaining candidate must go in the only remaining slot left on the\r\n" ); document.write( "list, in this case the 4th or last one.\r\n" ); document.write( "\r\n" ); document.write( "Answer = 24\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |