document.write( "Question 740432: I need some help solving a problem. The problem:\r
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document.write( "Find the standard form of the hyperbola given below. Find also the vertices, foci, and asymptotes, determine the eccentricity.\r
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Algebra.Com's Answer #451627 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the standard form of the hyperbola given below. Find also the vertices, foci, and asymptotes, determine the eccentricity.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "complete the square: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This is an equation of a hyperbola with horizontal transverse axis. \n" ); document.write( "Its standard form: \n" ); document.write( "For given hyperbola: \n" ); document.write( "center: (1,-1) \n" ); document.write( "a^2=8 \n" ); document.write( "a=√8≈2.8 \n" ); document.write( "vertices: (1±a,1)=(1±2.8,1)=(1.8,1) and (3.8,1) \n" ); document.write( "b^2=4 \n" ); document.write( "b=2 \n" ); document.write( "c^2=a^2+b^2=8+4=12 \n" ); document.write( "c=√12≈3.5 \n" ); document.write( "vertices: (1±c,-1)=(1±3.5,-1)=(2.5,-1) and (4.5,-1) \n" ); document.write( "eccentricity=c/a=√12/√8=√(3/2)≈1.2 \n" ); document.write( "asymptotes: (equations of lines that go thru center of the form: y=mx+b, m=slope, b=y-intercept) \n" ); document.write( "slopes of asymptotes for hyperbolas with horizontal transverse axis=±b/a=±2/√8 \n" ); document.write( ".. \n" ); document.write( "equation of asymptote with positive slope: \n" ); document.write( "y=2x/√8+b \n" ); document.write( "solve for b using coordinates of center: \n" ); document.write( "-1=2*1/√8+b \n" ); document.write( "b=-1-2/√8≈1.707 \n" ); document.write( "equation: \n" ); document.write( "y=2x/√8-1.707 \n" ); document.write( ".. \n" ); document.write( "equation of asymptote with negative slope: \n" ); document.write( "y=-2x/√8+b \n" ); document.write( "solve for b using coordinates of center: \n" ); document.write( "-1=-2*1/√8+b \n" ); document.write( "b=-1+2/√8≈-0.293 \n" ); document.write( "equation: \n" ); document.write( "y=-2x/√8-0.293 \n" ); document.write( ".. \n" ); document.write( "see graph below as a visual check: \n" ); document.write( "y=((x-1)^2/2-4)^.5-1\r \n" ); document.write( "\n" ); document.write( " |