document.write( "Question 740302: \"Write the equation of the line that satisfies the given condition: contains the point (-1,1) and is parallel to the line x+2y=3.\"\r
\n" ); document.write( "\n" ); document.write( "I'm not sure how to go about this one. Any way I could get clear step by step help with the problem?\r
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Algebra.Com's Answer #451552 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
1 x + 2 y = 3
\n" ); document.write( "Find the slope of this line
\n" ); document.write( "make y the subject
\n" ); document.write( "2 y = -1 x + 3
\n" ); document.write( "Divide by 2
\n" ); document.write( " y = - 1/2 x + 1 1/2
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = - 1/2
\n" ); document.write( "The slope of a line parallel to the above line will be the same
\n" ); document.write( "The slope of the required line will be - 1/2
\n" ); document.write( "m= - 1/2 ,point ( -1 , 1 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "1 = 1/ 2 + b
\n" ); document.write( "b= 0.5
\n" ); document.write( "m= - 1/2
\n" ); document.write( "Plug value of the slope and b in y = mx +b
\n" ); document.write( "The required equation is y = - 1/2 x + 1/ 2
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\n" ); document.write( "m.ananth@hotmail.ca
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