document.write( "Question 740308: \"A sum of $3300 is invested, part of it at 10% interest and the remainder at 12%. If the interest earned by the 12% investment is $143 more than the interest earned by the 10% investment, find the amount invested at each rate.\"\r
\n" ); document.write( "\n" ); document.write( "I would like help with setting up a proper equation and solving.\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #451551 by mananth(16946)\"\" \"About 
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12%-----------x
\n" ); document.write( "10%----------y\r
\n" ); document.write( "\n" ); document.write( "x+y=3000,,,,,,,,,,,,,,,,,,,,,,,,(1)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "12%x=10%y+143\r
\n" ); document.write( "\n" ); document.write( "12%x-10%y=143
\n" ); document.write( "multiply by 100
\n" ); document.write( "12x-10y=14300.....................(2)\r
\n" ); document.write( "\n" ); document.write( "1.00 x + 1.00 y = 3300.00 .............1
\n" ); document.write( "Total value
\n" ); document.write( "12.00 x -10.00 y = 14300.00 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 10.00
\n" ); document.write( "Multiply (2) by 1.00
\n" ); document.write( "10.00 x 10.00 y = 33000.00
\n" ); document.write( "12.00 x -10.00 y = 14300.00
\n" ); document.write( "Add the two equations
\n" ); document.write( "22.00 x = 47300.00
\n" ); document.write( "/ 22.00
\n" ); document.write( "x = 2150.00
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1.00 x + 1.00 y = 3300.00
\n" ); document.write( "2150.00 + y = 3300.00
\n" ); document.write( " y = 3300.00 -2150.00
\n" ); document.write( " y = 1150.00
\n" ); document.write( " y = 1150.00
\n" ); document.write( "12%---------$2150
\n" ); document.write( "10%---------$1150
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