document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=740309>Question 740309</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I did not understand my teacher's explanation in class. I would very much appreciate you assistance and I will take notes for the future. Thank you! <BR>\n" );
document.write( "Find shaded area (the triangle is equilateral)<BR>\n" );
document.write( "I will post a picture. <BR>\n" );
document.write( "http://screencast.com/t/Fv2HJVOreHE<BR>\n" );
document.write( "Thank You! Please help I need this for tomorrow I promise to write down everything you help me with. Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451550 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw a perpendicular from O to one of its base. SAY OT.\r<BR>\n" );
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document.write( "the triangle formed is 30-60-90 \r<BR>\n" );
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document.write( "with hypotenuse as 10. \r<BR>\n" );
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document.write( "side opposite to 60 deg is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%283%29%2F2%29%2Ahypotenuse ALIGN=MIDDLE  ALT=\"%28sqrt%283%29%2F2%29%2Ahypotenuse\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "the side will be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5sqrt%283%29 ALIGN=MIDDLE  ALT=\"5sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "the chord of the circle is the side of the triangle.\r<BR>\n" );
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document.write( "side of triangle = 2*<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5sqrt%283%29 ALIGN=MIDDLE  ALT=\"5sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10sqrt%283%29 ALIGN=MIDDLE  ALT=\"10sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Area of equilateral triangle = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28sqrt%283%29%2F4+%29%2A+s%5E2 ALIGN=MIDDLE  ALT=\"%28sqrt%283%29%2F4+%29%2A+s%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "s= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10sqrt%283%29 ALIGN=MIDDLE  ALT=\"10sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "AREA =  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%28sqrt%283%29%29%2F4+%29%2A+%2810sqrt%283%29%29%5E2 ALIGN=MIDDLE  ALT=\"%28%28sqrt%283%29%29%2F4+%29%2A+%2810sqrt%283%29%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >=129.9\r<BR>\n" );
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document.write( "Area of circle = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+pi+%2A+r%5E2 ALIGN=MIDDLE  ALT=\"+pi+%2A+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "=3.14 *10*10\r<BR>\n" );
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document.write( "=314 sq units\r<BR>\n" );
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document.write( "the difference is the area of shaded portion<BR>\n" );
document.write( "area of circle - area of triangle\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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