document.write( "Question 740092: I'm having trouble with a question in my lesson. Could I have some help?\r
\n" ); document.write( "\n" ); document.write( "(-1 + [SQRT(3)]i)^3 \r
\n" ); document.write( "\n" ); document.write( "These are the options:\r
\n" ); document.write( "\n" ); document.write( "A) 2 + 2[SQRT(3)]i
\n" ); document.write( "B) -2 - 2[SQRT(3)]i
\n" ); document.write( "C) 0
\n" ); document.write( "D) -8
\n" ); document.write( "E) -8 + 8[SQRT(3)]i
\n" ); document.write( "F) 8
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Algebra.Com's Answer #451528 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
You can calculate \"%28-1%2Bsqrt%283%29i%29%5E3\" as you would calculate the cube of any binomial, using the formula
\n" ); document.write( "\"%28a%2Bb%29%5E3=a%5E3%2B3a%5E2b%2B3ab%5E2%2Bb%5E3\"
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\n" ); document.write( "If you already learned about the polar form of complex numbers, you could transform the number into its polar form, if that made it easier for you.
\n" ); document.write( "\"-1%2Bsqrt%283%29i=2%28cos%28120%5Eo%29%2Bi%2Asin%28120%5Eo%29%29\" has
\n" ); document.write( "absolute value (or modulus): \"r=2+=sqrt%28%28-1%29%5E2%2B%28sqrt%283%29%29%5E2%29\"
\n" ); document.write( "argument: \"theta=120%5Eo\"
\n" ); document.write( "Multiplication and powers are easier in polar form.
\n" ); document.write( "To multiply, you just multiply the absolute values and add the arguments.
\n" ); document.write( "So
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