document.write( "Question 740160: Please Help! \r
\n" ); document.write( "\n" ); document.write( " 25= √5^(2x+6)\r
\n" ); document.write( "\n" ); document.write( "explain the strategy used in solving this equation the way you did
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Algebra.Com's Answer #451509 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
first note that sqrt(5) = 5^1/2\r
\n" ); document.write( "\n" ); document.write( "with that we can rewrite the equation\r
\n" ); document.write( "\n" ); document.write( "25 = (5^1/2)^(2x+6)\r
\n" ); document.write( "\n" ); document.write( "multiply the exponents on the right side of = sign\r
\n" ); document.write( "\n" ); document.write( "25 = 5^(x+3)\r
\n" ); document.write( "\n" ); document.write( "and x = -1 since 5^2 = 25\r
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