document.write( "Question 739966: find the sum of all natural numbers between 1 and 100 which are not exactly divisible by 2 or 3? \n" ); document.write( "
Algebra.Com's Answer #451499 by KMST(5328)![]() ![]() You can put this solution on YOUR website! We can find that sum if we find the sum for all the natural numbers between i and 100, and for the sums for those numbers that are not supposed to be counted. \n" ); document.write( " \n" ); document.write( "The sum of all integers from \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The sum of all natural numbers between 1 and 100 is \n" ); document.write( "The sum of all natural numbers between 1 and 100 that are exactly divisible by 2 is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The sum of all natural numbers between 1 and 100 that are exactly divisible by 3 is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "All numbers that are exactly divisible by 2 and 3 are divisible by 6, and all numbers exactly divisible by 6 are divisible by 2 and 3. \n" ); document.write( "The sum of all natural numbers between 1 and 100 that are exactly divisible by 2 and 3 is the sum of all natural numbers between 1 and 100 that are exactly divisible by 6, which can be calculated as \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "To find the sum we want, we start with the sum of all the natural numbers from 1 to 100; \n" ); document.write( "we subtract the sum of those that are exactly divisible by 2; \n" ); document.write( "we subtract the sum of those that are exactly divisible by 3, \n" ); document.write( "and since in the previous subtractions we subtracted the numbers divisible bt 6 twice, \n" ); document.write( "we add the sum of natural numbers between 1 and 100 that are exactly divisible by 6. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "or if you prefer, you can calculate it as \n" ); document.write( " |