document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=739983>Question 739983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in 12 yrs a man will be 3 times as old as his son,the difference of their present age is 30 yrs.find their present age </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451455 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451455\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F-S=30 OR F=30+S<BR>\n" );
document.write( "F+12=3(S+12)<BR>\n" );
document.write( "F+12=3S+36<BR>\n" );
document.write( "30+S+12=3S+36<BR>\n" );
document.write( "S-3S=36-30-12<BR>\n" );
document.write( "-2S=-6<BR>\n" );
document.write( "S=-6/-2<BR>\n" );
document.write( "S=3 YEARS OLD NOW.<BR>\n" );
document.write( "F-3=30<BR>\n" );
document.write( "F=30+3<BR>\n" );
document.write( "F=33 YEARS OLD NOW.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "33+12=3(3+12)<BR>\n" );
document.write( "45=3*15<BR>\n" );
document.write( "45=45 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );