document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=739965>Question 739965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of 4 term of an A.p is 4 and the sum of the product of the first and the last and the 2 middle term is -3 find the numbers?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451437 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the 4 numbers be <BR>\n" );
document.write( "a-3d,a-d,a+d,a+3d\r<BR>\n" );
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document.write( "a-3d+a-d+a+d+a+3d=4\r<BR>\n" );
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document.write( "4a=4<BR>\n" );
document.write( "a=1\r<BR>\n" );
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document.write( "(a-d)(a+d)+(a-3d)(a+3d)=-3\r<BR>\n" );
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document.write( "a^2-d^2+a^2-9d^2=-3\r<BR>\n" );
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document.write( "2a^2-10d^2=-3\r<BR>\n" );
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document.write( "but a=1<BR>\n" );
document.write( "2-10d^2=-3<BR>\n" );
document.write( "10d^2=5\r<BR>\n" );
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document.write( "d^2=1/2\r<BR>\n" );
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document.write( "d= +/- 1/sqrt(2)\r<BR>\n" );
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document.write( "1-(3/sqrt(2)), 1-1/sqrt(2),1+1/sqrt(2), 1+(3/sqrt(2))\r<BR>\n" );
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document.write( "plug d= -1/sqrt(2) and get the other 4 numbers </SPAN>\n" );
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