document.write( "Question 739958: Beth is three years older than Jay. Find their present ages if the product of Beth's age is four years from now and Jay's age three years ago is 75.Thank You!
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Algebra.Com's Answer #451428 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+b+\"$ = Beth's age now
\n" ); document.write( "Let $\"+j+\"$ = Jay's age now
\n" ); document.write( " $\"+b+%2B+4+\"$ = Beth's age in $\"+4+\"$ years
\n" ); document.write( " $\"+j+-+3+\"$ = Jay's age 3 years ago
\n" ); document.write( "-----------------------------
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"+b+=+j+%2B+3+\"$
\n" ); document.write( "(2) $\"+%28+b+%2B+4+%29%2A%28+j+-+3+%29+=+75+\"$
\n" ); document.write( "--------------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+%28+j+%2B+3+%2B+4+%29%2A%28+j+-+3+%29+=+75+\"$
\n" ); document.write( "(2) $\"+%28+j+%2B+7+%29%2A%28+j+-+3+%29+=+75+\"$
\n" ); document.write( "(2) $\"+j%5E2+%2B+7j+-+3j+-+21+=+75+\"$
\n" ); document.write( "(2) $\"+j%5E2+%2B+4j+-+96+=+0+\"$
\n" ); document.write( "By looking at this I can see:
\n" ); document.write( "(2) $\"+%28+j+%2B+12+%29%2A%28+j+-+8+%29+=+0+\"$
\n" ); document.write( " $\"+j+=+8+\"$ ( ignore negative answer )
\n" ); document.write( "and, since,
\n" ); document.write( "(1) $\"+b+=+j+%2B+3+\"$
\n" ); document.write( "(1) $\"+b+=+11+\"$
\n" ); document.write( "Beth is 11 and Jay is 8
\n" ); document.write( "check:
\n" ); document.write( "(2) $\"+%28+b+%2B+4+%29%2A%28+j+-+3+%29+=+75+\"$
\n" ); document.write( "(2) $\"+%28+11+%2B+4+%29%2A%28+8+-+3+%29+=+75+\"$
\n" ); document.write( "(2) $\"+15%2A5+=+75+\"$
\n" ); document.write( "(2) $\"+75+=+75+\"$
\n" ); document.write( "OK\r
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