document.write( "Question 739875: Ivan had $10,000 to invest. He invested some in an account that paid 7% simple interest per year and some in an account that paid 5% simple interest per year. After 1 year he received a total of $680 in interest. How much did he invest in each account?\r
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document.write( "(I tried to set up a table, but all I know is the amount of time, the total principal and the total interest. I can't figure out what variables to use or where to place them to form an equation to solve. \n" );
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Algebra.Com's Answer #451413 by mananth(16946) You can put this solution on YOUR website! Part I 5.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 7.00% per annum ------------ Amount invested = y \n" ); document.write( " 10000 \n" ); document.write( "Interest----- 680.00 \n" ); document.write( " \n" ); document.write( "Part I 5.00% per annum ---x \n" ); document.write( "Part II 7.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 10000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "5.00% x + 7.00% y= 680 \n" ); document.write( "Multiply by 100 \n" ); document.write( "5 x + 7 y= 68000.00 --------2 \n" ); document.write( "Multiply (1) by -5 \n" ); document.write( "we get \n" ); document.write( "-5 x -5 y= -50000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x 2 y= 18000 \n" ); document.write( "divide by 2 \n" ); document.write( " y = 9000 \n" ); document.write( "Part I 5.00% $ 1000 \n" ); document.write( "Part II 7.00% $ 9000 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "1000 --------- 5.00% ------- 50.00 \n" ); document.write( "9000 ------------- 7.00% ------- 630.00 \n" ); document.write( "Total -------------------- 680.00 \n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |