document.write( "Question 739904: 1. Solve the following simple interest word problem:\r
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document.write( "Sue, a recent retiree, requires $6,000 per year in extra income. She has $50,000 to invest and can invest in B-rated bonds paying 15% per year or in a certificate of deposit (CD) paying 7% per year. How much money should be invested in each to realize exactly $6,000 in interest per year?\r
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document.write( "2. Solve the following time-distance word problem:\r
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document.write( "A motorboat heads upstream a distance of 24 miles on a river whose current is running at 3 miles per hour (mi/hr). The trip up and back takes 6 hours. Assuming that the motor boat maintained a constant speed relative to the water, what was its speed?
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Algebra.Com's Answer #451412 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 15.00% per annum ------------- Amount invested =x \n" ); document.write( "Part II 7.00% per annum ------------ Amount invested = y \n" ); document.write( " 50000 \n" ); document.write( "Interest----- 6000.00 \n" ); document.write( " \n" ); document.write( "Part I 15.00% per annum ---x * \n" ); document.write( "Part II 7.00% per annum ---y \n" ); document.write( "Total investment \n" ); document.write( "x + 1 y= 50000 -------------1 \n" ); document.write( "Interest on both investments \n" ); document.write( "15.00% x + 7.00% y= 6000 \n" ); document.write( "Multiply by 100 \n" ); document.write( "15 x + 7 y= 600000.00 --------2 \n" ); document.write( "Multiply (1) by -15 \n" ); document.write( "we get \n" ); document.write( "-15 x -15 y= -750000.00 \n" ); document.write( "Add this to (2) \n" ); document.write( "0 x -8 y= -150000 \n" ); document.write( "divide by -8 \n" ); document.write( " y = 18750 - x) \n" ); document.write( "Part I 15.00% $ 31250 \n" ); document.write( "Part II 7.00% $ 18750 \n" ); document.write( " \n" ); document.write( "CHECK \n" ); document.write( "31250 --------- 15.00% ------- 4687.50 \n" ); document.write( "18750 ------------- 7.00% ------- 1312.50 \n" ); document.write( "Total -------------------- 6000.00 \n" ); document.write( "------------\r \n" ); document.write( "\n" ); document.write( "Boat speed x mph \n" ); document.write( "current speed 3 mph \n" ); document.write( " \n" ); document.write( "Distance with wind 24 miles \n" ); document.write( "Distance against wind 24 miles \n" ); document.write( " \n" ); document.write( "spee with current x + 3 mph \n" ); document.write( "speed against x 3 mph \n" ); document.write( "Total time = 6 hours \n" ); document.write( "Time with current= 24 /( x + 25 ) \n" ); document.write( "time against current 24 / ( x -25 ) \n" ); document.write( " \n" ); document.write( "Time with current + time against = 10 hours \n" ); document.write( " \n" ); document.write( "24 /( x + 3 ) + 24 /(x -3 ) = 6 \n" ); document.write( "LCD = ( x + 3 )* (x -3 ) \n" ); document.write( "multiply the equation by the LCD \n" ); document.write( "we get \n" ); document.write( "24 * (x -3 )+ 24 (x + 3 )= 6 (x^2- 9 ) \n" ); document.write( "24 x -72 + 24 x + 72 )= 6 X^2 54 \n" ); document.write( "48 x 0 = 10 X^2 -54 \n" ); document.write( "6 X^2 -48 x 0 + -54 = 0 \n" ); document.write( "6 X^2+ -48 x+ -54 = 0 OK \n" ); document.write( "/ 1 \n" ); document.write( "6 X^2 -48 x -54 = 0 \n" ); document.write( " \n" ); document.write( " Find the roots of the equation by quadratic formula \n" ); document.write( " \n" ); document.write( " a= 6 b= -48 c= -54 \n" ); document.write( " \n" ); document.write( " b^2-4ac= 2304 - -1296 \n" ); document.write( " b^2-4ac= 3600 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " x1=( 48 + 60 )/ 12 \n" ); document.write( " x1= 9 \n" ); document.write( " x2=( 48 -60 ) / 12 \n" ); document.write( " x2= -1 \n" ); document.write( " Ignore negative value mph \n" ); document.write( " x = 9 \n" ); document.write( " \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |