document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64483>Question 64483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I don't even know where to start with this one, looking for help\r<BR>\n" );
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document.write( "Solve for x\r<BR>\n" );
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document.write( "27.)	log x = (2/3) log 8 – (2 log 5 + log 2)\r<BR>\n" );
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document.write( "28.)	log (x – 1) + log (x – 1) = log 3 <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45141 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45141\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 27.) log x = (2/3) log 8 – (2 log 5 + log 2)<BR>\n" );
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document.write( "You don't even need to find the logs of these, use the exponent equiv & rules:<BR>\n" );
document.write( "log x = log(8^(2/3)) - log(5^2) + log (2)<BR>\n" );
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document.write( "you know that Cube root of 8 is 2, and 2^2 = 4, 5^2 is 25, so you have:<BR>\n" );
document.write( "log x = log(4) - (log(25) + log(2))<BR>\n" );
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document.write( "Adding logs is that same as multiply so you have:<BR>\n" );
document.write( "log x = log(4) - log(50)<BR>\n" );
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document.write( "Subtracting logs is the same as dividing so you have:<BR>\n" );
document.write( "log x = log(4/50)<BR>\n" );
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document.write( "if the log of x = log (4/50) then<BR>\n" );
document.write( "x = 4/50<BR>\n" );
document.write( "x = .08<BR>\n" );
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document.write( "28.) log (x – 1) + log (x – 1) = log 3<BR>\n" );
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document.write( "You are adding like terms so you have:<BR>\n" );
document.write( "2*log(x-1) = log 3<BR>\n" );
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document.write( "Find the log of 3<BR>\n" );
document.write( "2*log(x-1) = .477<BR>\n" );
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document.write( "Divide both sids by 2:<BR>\n" );
document.write( "log(x-1) = .477/2<BR>\n" );
document.write( "log(x-1) = .2385<BR>\n" );
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document.write( "Find the anti log (10^) of both sides:<BR>\n" );
document.write( "x - 1 = 1.732<BR>\n" );
document.write( "x = 1.732 + 1<BR>\n" );
document.write( "x = 2.732<BR>\n" );
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document.write( "Check using a calc: <BR>\n" );
document.write( "2*log(1.732) = log(3)<BR>\n" );
document.write( "2 * .2385 = .477<BR>\n" );
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