document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=739876>Question 739876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to find the answer to and show the steps of these two equations but I have no clue what to do or where to start.It's part of a project which is a big portion of my grade, any help would be great.\r<BR>\n" );
document.write( "\n" );
document.write( "The equations are:\r<BR>\n" );
document.write( "\n" );
document.write( "133(b)+6(c)=1000\r<BR>\n" );
document.write( "\n" );
document.write( "2.07(b)+0.2(c)=8<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451372 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 133(b)+6(c)=1000<BR>\n" );
document.write( "2.07(b)+0.2(c)=8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "133b+6c=1000<BR>\n" );
document.write( "2.07b+0.2c=8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-------------------------------\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Solve equation 1 for 'c'\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "133b+6c=1000\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "6c=1000-133b\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c=(1000-133b)/6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "------------------\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Plug this into the second equation\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2.07b+0.2c=8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2.07b+0.2( (1000-133b)/6 )=8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2.07b+(0.2*1000-0.2*133b)/6=8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2.07b+(200-26.6b)/6=8\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "6*2.07b+6*(200-26.6b)/6=6*8 ... Multiply EVERY term by the LCD 6 to clear out fractions\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "12.42b + 200 - 26.6b = 48\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-14.18b + 200 = 48\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-14.18b = 48 - 200\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-14.18b = -152\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "b = -152/(-14.18)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "b = 10.71932299 (this is approximate)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c = (1000-133b)/6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c = (1000-133*10.71932299)/6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c = (1000-1425.66995767)/6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c = -425.66995767/6\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c = -70.944992945 (this is approximate too)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-------------------------------------------------------\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So the approximate solutions are\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "b = 10.71932299 \r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "c = -70.944992945<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );