document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=739847>Question 739847</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of an angle is 4y°. Find the measure of its supplement<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451357 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451357\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = supplment of angle 4y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "The two angles must add to 180 since they are supplements, so\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x+4y = 180\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x+4y-4y = 180-4y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x+0y = 180-4y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x+0 = 180-4y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = 180-4y\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "x = -4y + 180\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So the final answer is <font color=\"red\">-4y + 180</font> </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );