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document.write( "Present age of the father is 3 times that of his sons. The sum of that ages 10 years ago is as much as their present age of the father. Find the ages \n" );
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Algebra.Com's Answer #451295 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! F=3X \n" ); document.write( "S=X \n" ); document.write( "3X-10+X-10=3X \n" ); document.write( "3X-3X+X=10+10 \n" ); document.write( "X=20 AGE OF THE SON NOW. \n" ); document.write( "3*20=60 AGE OF THE FATHER NOW. \n" ); document.write( "PROOF: \n" ); document.write( "60-10+20-10=60 \n" ); document.write( "80-20=60 \n" ); document.write( "60=60 \n" ); document.write( " |