document.write( "Question 739732: \r
\n" ); document.write( "\n" ); document.write( "Present age of the father is 3 times that of his sons. The sum of that ages 10 years ago is as much as their present age of the father. Find the ages
\n" ); document.write( "

Algebra.Com's Answer #451295 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
F=3X
\n" ); document.write( "S=X
\n" ); document.write( "3X-10+X-10=3X
\n" ); document.write( "3X-3X+X=10+10
\n" ); document.write( "X=20 AGE OF THE SON NOW.
\n" ); document.write( "3*20=60 AGE OF THE FATHER NOW.
\n" ); document.write( "PROOF:
\n" ); document.write( "60-10+20-10=60
\n" ); document.write( "80-20=60
\n" ); document.write( "60=60
\n" ); document.write( "
\n" );