document.write( "Question 739553: can anyone solve these and explain how please???\r
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document.write( "log(1/5)x=-2\r
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document.write( "log(x)125=-3\r
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Algebra.Com's Answer #451169 by Alan3354(69443) You can put this solution on YOUR website! log(1/5)x=-2 \n" ); document.write( "------------- \n" ); document.write( "The log is the exponent. \n" ); document.write( "--> \n" ); document.write( "x = 25 \n" ); document.write( "------ \n" ); document.write( "log(x)125=-3 \n" ); document.write( "Remember The log is the exponent. \n" ); document.write( "--> \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "If you recognize that 5^3 = 125, then \n" ); document.write( "1/x = 5 \n" ); document.write( "x = 1/5 \n" ); document.write( "------------ \n" ); document.write( " \n" ); document.write( " |