document.write( "Question 739553: can anyone solve these and explain how please???\r
\n" ); document.write( "\n" ); document.write( "log(1/5)x=-2\r
\n" ); document.write( "\n" ); document.write( "log(x)125=-3\r
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Algebra.Com's Answer #451169 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
log(1/5)x=-2
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\n" ); document.write( "The log is the exponent.
\n" ); document.write( "--> \"%281%2F5%29%5E%28-2%29+=+x\"
\n" ); document.write( "x = 25
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\n" ); document.write( "log(x)125=-3
\n" ); document.write( "Remember The log is the exponent.
\n" ); document.write( "--> \"x%5E%28-3%29+=+125\"
\n" ); document.write( "\"1%2Fx%5E3+=+125\"
\n" ); document.write( "\"%281%2Fx%29%5E3+=+125\"
\n" ); document.write( "If you recognize that 5^3 = 125, then
\n" ); document.write( "1/x = 5
\n" ); document.write( "x = 1/5
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