document.write( "Question 739485: name the vertex, focus, and directrix of y=1/4(x-2)^2 \n" ); document.write( "

Algebra.Com's Answer #451132 by lwsshak3(11628) $\"\"$ $\"About$

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name the vertex, focus, and directrix of
\n" ); document.write( "y=1/4(x-2)^2
\n" ); document.write( "(x-2)^2=4y
\n" ); document.write( "This is an equation of a parabola that opens upward.
\n" ); document.write( "Its basic form: (x-h)^2=4p(y-k), (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "For given equation:
\n" ); document.write( "vertex: (2,0)
\n" ); document.write( "axis of symmetry: x=2
\n" ); document.write( "4p=4
\n" ); document.write( "p=1
\n" ); document.write( "focus: (2,1) (p-distance above vertex on the axis of symmetry)
\n" ); document.write( "directrix: y=-1 (p-distance below vertex on the axis of symmetry) \n" ); document.write( "

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