document.write( "Question 739216: ankita travel 14 km to home partially by rickshaw AND BY BUS SHE TAKES 1 2 HR IF SHE TRAVELS BY RICKSHAW AND THE REMAING DISTANCE BY BUS ON OTHER HAND IF SHE TRAVELS 4 KM BY RICKSHAW AND REMAING DISTANCE BY BUS SHE TAKES 9 MINUTES LONGER\r
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Algebra.Com's Answer #451069 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Will try to make sense of this.
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\n" ); document.write( "Ankita travel 14 km home, partially by rickshaw and by bus.
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\n" ); document.write( "She takes \"1%2F2\" hr if is she travels 4 km by Rickshaw and takes the remaining distance by by bus.
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\n" ); document.write( "On the other hand, if she travels 10 km by rickshaw, and the remaining distance by bus, she takes 9 min longer.
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\n" ); document.write( "Assume you want to find the speed of the rickshaw and speed of the bus.
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\n" ); document.write( "let r = speed of the rickshaw
\n" ); document.write( "let b = speed of the bus
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\n" ); document.write( "Write an time equation for the 1st statement (time = dist/speed):
\n" ); document.write( "\"She takes \"1%2F2\" hr if is she travels 4 km by Rickshaw and takes the remaining distance by by bus.\"
\n" ); document.write( "\"4%2Fr\" + \"10%2Fb\" = \"1%2F2\"
\n" ); document.write( "multiply equation by 2rb, to get rid of the denominators
\n" ); document.write( "2rb*\"4%2Fr\" + 2rb*\"10%2Fb\" = 2rb*\"1%2F2\"
\n" ); document.write( "cancel the denominators
\n" ); document.write( "8b + 20r = rb
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\n" ); document.write( "Write a time equation for the 2nd statement (time = dist/speed):
\n" ); document.write( "\"if she travels 10 km by rickshaw, and the remaining distance by bus, she takes 9 min longer.\"
\n" ); document.write( "\"10%2Fr\" + \"4%2Fb\" = 30 + 9
\n" ); document.write( "\"10%2Fr\" + \"4%2Fb\" = 39
\n" ); document.write( "change 39 min to hr (we're finding the speed in km/hr
\n" ); document.write( "\"10%2Fr\" + \"4%2Fb\" = \"39%2F60\"
\n" ); document.write( "\"10%2Fr\" + \"4%2Fb\" = \"13%2F20\"
\n" ); document.write( "multiply equation by 20rb, to get rid of the denominators
\n" ); document.write( "20rb*\"10%2Fr\" + 20rb*\"4%2Fb\" = 20rb*\"13%2F20\"
\n" ); document.write( "cancel the denominators
\n" ); document.write( "200b + 80r = 13rb
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\n" ); document.write( "multiply the first equation by 4, subtract from the above equation
\n" ); document.write( "200b + 80r = 13rb
\n" ); document.write( "32b + 80r = 4rb
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\n" ); document.write( "168b = 9rb
\n" ); document.write( "divide both sides by by b
\n" ); document.write( "168 = 9r
\n" ); document.write( "r = 168/9
\n" ); document.write( "r = 18.67 km/hr is the speed of the rickshaw (Is that possible?)
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\n" ); document.write( "Find the speed of the bus
\n" ); document.write( "8b + 20r = rb
\n" ); document.write( "8b + 20(18.67) = 18.67b\r
\n" ); document.write( "\n" ); document.write( "373.3 = 18.67b - 8b
\n" ); document.write( "373.3 = 10.67b
\n" ); document.write( "b = 373.3/10.67
\n" ); document.write( "b ~ 35 km/hr is the speed of the bus
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\n" ); document.write( "See if that checks out in the first statement, find the travel time of each
\n" ); document.write( "\"4%2F18.67\" + \"10%2F35\" =
\n" ); document.write( ".214 + .286 = .5 hrs\r
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