document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=739217>Question 739217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
document.write( "\n" );
document.write( "The length of a rectangle is three feet more than twice the width. The area is 90 square feet. What are the dimensions of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451066 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451066\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> AREA=LW<BR>\n" );
document.write( "L=2W+3<BR>\n" );
document.write( "90=(2W+3)W<BR>\n" );
document.write( "90=2W^2+3W<BR>\n" );
document.write( "2W^2+3X-90=0<BR>\n" );
document.write( "(W-6)(2W+15)=0<BR>\n" );
document.write( "W-6=0<BR>\n" );
document.write( "W=6 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=2*6+3<BR>\n" );
document.write( "L=12+3=15 ANS.<BR>\n" );
document.write( "PROOF\"<BR>\n" );
document.write( "90=6*15<BR>\n" );
document.write( "90=90 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );