document.write( "Question 738944: A ball is thrown downward from the top of a 180 foot building with an initial velocity of 20 feet per second. The height of the ball h after t seconds is given by the equation h=-16t^2-20t+180. How long after the ball is thrown will it be 50 feet from the ground? Round the result to the nearest tenth of a second. \n" ); document.write( "
Algebra.Com's Answer #451043 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 50=-16t^2-20t+180 \n" ); document.write( " t=2.29315 \n" ); document.write( "t=2.3 \n" ); document.write( " |