document.write( "Question 739132: Running at an average rate of 6 meters per
\n" ); document.write( "second, a sprinter ran to the end of a track. The sprinter then
\n" ); document.write( "jogged back to the starting point at an average rate of 2 meters
\n" ); document.write( "per second. The total time for the sprint and the jog back was
\n" ); document.write( "2 minutes 40 seconds. Find the length of the track.
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Algebra.Com's Answer #451023 by ankor@dixie-net.com(22740)\"\" \"About 
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Running at an average rate of 6 meters per second, a sprinter ran to the end of a track.
\n" ); document.write( " The sprinter then jogged back to the starting point at an average rate of 2 meters per second.
\n" ); document.write( " The total time for the sprint and the jog back was 2 minutes 40 seconds.
\n" ); document.write( " Find the length of the track.
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\n" ); document.write( "Since we are dealing in m/sec, change 2 min 40 sec to 160 seconds
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\n" ); document.write( "let d = the length of the track
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\n" ); document.write( "Write a time equation; time = dist/speed
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\n" ); document.write( "Sprint time + jog time = 2 min 40 sec
\n" ); document.write( "\"d%2F6\" + \"d%2F2\" = 160
\n" ); document.write( "mult by 6 to clear the denominators
\n" ); document.write( "d + 3d = 6(160)
\n" ); document.write( "4d = 960
\n" ); document.write( "d = 240 meters is the length of the track
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\n" ); document.write( "Check this:
\n" ); document.write( "240/6 = 40 sec
\n" ); document.write( "240/2 = 120 sec
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\n" ); document.write( "tot time 160 sec\r
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