document.write( "Question 739132: Running at an average rate of 6 meters per
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document.write( "second, a sprinter ran to the end of a track. The sprinter then
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document.write( "jogged back to the starting point at an average rate of 2 meters
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document.write( "per second. The total time for the sprint and the jog back was
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document.write( "2 minutes 40 seconds. Find the length of the track. \n" );
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Algebra.Com's Answer #451023 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Running at an average rate of 6 meters per second, a sprinter ran to the end of a track. \n" ); document.write( " The sprinter then jogged back to the starting point at an average rate of 2 meters per second. \n" ); document.write( " The total time for the sprint and the jog back was 2 minutes 40 seconds. \n" ); document.write( " Find the length of the track. \n" ); document.write( ": \n" ); document.write( "Since we are dealing in m/sec, change 2 min 40 sec to 160 seconds \n" ); document.write( ": \n" ); document.write( "let d = the length of the track \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( ": \n" ); document.write( "Sprint time + jog time = 2 min 40 sec \n" ); document.write( " \n" ); document.write( "mult by 6 to clear the denominators \n" ); document.write( "d + 3d = 6(160) \n" ); document.write( "4d = 960 \n" ); document.write( "d = 240 meters is the length of the track \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this: \n" ); document.write( "240/6 = 40 sec \n" ); document.write( "240/2 = 120 sec \n" ); document.write( "------------------ \n" ); document.write( "tot time 160 sec\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |