document.write( "Question 738978: Determine two whole numbers such that the first number increased by triple the second number is 24.
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document.write( "If the first number is squared and decreased by five times itself, the result is 13 less than the second number. \n" );
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Algebra.Com's Answer #451016 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let the two numbers be a & b, write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "Determine two whole numbers such that the first number increased by triple the second number is 24. \n" ); document.write( "a + 3b = 24 \n" ); document.write( "3b = (24-a) \n" ); document.write( "divide by 3 \n" ); document.write( "b = (8 - a/3); use this form for substitution \n" ); document.write( ": \n" ); document.write( "If the first number is squared and decreased by five times itself, the result is 13 less than the second number. \n" ); document.write( "a^2 - 5a = b - 13 \n" ); document.write( "Replace b with (8 - a/3) \n" ); document.write( "a^2 - 5a = 8 - a/3 - 13 \n" ); document.write( "a^2 - 5a = - a/3 - 5 \n" ); document.write( "mult by 3 to get rid of the denominator \n" ); document.write( "3a^2 - 15a = -a - 15 \n" ); document.write( "Combine as a quadratic equation on the left \n" ); document.write( "3a^2 - 15a + a + 15 = 0 \n" ); document.write( "3a^2 - 14a + 15 = 0 \n" ); document.write( "factors to \n" ); document.write( "(3a-5)(a-3) = 0 \n" ); document.write( "only integer solution \n" ); document.write( "a = 3 \n" ); document.write( "find b \n" ); document.write( "b = 8 - 3/3 \n" ); document.write( "b = 7 \n" ); document.write( "; \n" ); document.write( "; \n" ); document.write( "See if that works in the given statements \n" ); document.write( "\"the first number increased by triple the second number is 24.\" \n" ); document.write( "3 + 3(7) = 24 \n" ); document.write( "\"first number is squared and decreased by five times itself, the result is 13 less than the second number.\" \n" ); document.write( "3^2 - 5(3) = 7 - 13 \n" ); document.write( "9 - 15 = -6 \n" ); document.write( " \n" ); document.write( " |