document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=739073>Question 739073</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If in a rectangle, the length is increaded and the breadth is reduced by 2 units each, the area is redueced by 28sq units. If the length is reduced by one unit and beadth increased by 2 units, the area increases by 33sq units. find the dimensionsof rectangle <BR>\n" );
document.write( "Please answer in manner like <BR>\n" );
document.write( "let .... be x <BR>\n" );
document.write( "let .... be y <BR>\n" );
document.write( "please answer </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #451006 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=451006\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First description:<BR>\n" );
document.write( "area is xy.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x%2B2%29%28y-2%29=xy-28 ALIGN=MIDDLE  ALT=\"%28x%2B2%29%28y-2%29=xy-28\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Second Description:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-1%29%28y%2B2%29=xy%2B33 ALIGN=MIDDLE  ALT=\"%28x-1%29%28y%2B2%29=xy%2B33\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "Performing the left-side multiplications will give an xy number on the left sides; and because when you subtract xy from left and right sides on both equations, the xy number is eliminated.  You obtain the system:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y-2x-4=-28 ALIGN=MIDDLE  ALT=\"2y-2x-4=-28\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-y%2B2x-2=33 ALIGN=MIDDLE  ALT=\"-y%2B2x-2=33\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Reform as the equivalent system: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x-y=12%29 ALIGN=MIDDLE  ALT=\"highlight%28x-y=12%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > AND <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%282x-y=35%29 ALIGN=MIDDLE  ALT=\"highlight%282x-y=35%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Subtract first equation from second equation and obtain <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=23%29 ALIGN=MIDDLE  ALT=\"highlight%28x=23%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >... and pick either equation to find y. </SPAN>\n" );
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