document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=738780>Question 738780</A>: <I><SPAN STYLE=\"word-break: break-all;\"> With a wind behind it, Glenn's pigeon flies 72 miles from Santa Rosa to Cloverdale in 6 hours. The return trip takes 8 hours because the pigeon flies into the wind. If the wind speed is the same on each trip, find the speed of the pigeon in still air and find the wind speed.\r<BR>\n" );
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document.write( "I know how to solve a system of equations, but i dont know how to set this word problem up, please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450923 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450923\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we use rate * time = distance and we have the two equations\r<BR>\n" );
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document.write( "6*rate = 72  and<BR>\n" );
document.write( "8*rate = 72\r<BR>\n" );
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document.write( "so the two rates are 12 mph with the wind and 9 mph against the wind\r<BR>\n" );
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document.write( "this tells us that the wind is 3 mph \r<BR>\n" );
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document.write( "now in the formula 6*12=72, the wind contributes 3*6=18 miles\r<BR>\n" );
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document.write( "subtract 18 from 72 and we get 54 and\r<BR>\n" );
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document.write( "we now have 6 * r = 54 or the rate of the pigeon in still air is 9 mph </SPAN>\n" );
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