document.write( "Question 738731: the area of a rectangular slab of sidewalk is 45 square feet. its length is 3 feet more than four times the width.find the length and the width.
\n" ); document.write( "Let width be x feet
\n" ); document.write( "Then length = 4x+3
\n" ); document.write( "Area = x*(4x+3)
\n" ); document.write( "which is equal to 45 (given)
\n" ); document.write( "Therefore
\n" ); document.write( "x*(4x+3)= 45
\n" ); document.write( "4x^2+3x = 45
\n" ); document.write( "4x^2 + 3x -45=0
\n" ); document.write( "4x^2 + 15x -12x -45=0
\n" ); document.write( "x*(4x+15) -3*(4x+15)=0
\n" ); document.write( "(x-3)(4x+15)=0
\n" ); document.write( "so x=3 or 15/4
\n" ); document.write( "Ans : Length = 15ft and width=3ft
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #450903 by mathstutor494(120) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let width be x feet
\n" ); document.write( "Then length = 4x+3
\n" ); document.write( "Area = x*(4x+3)which is equal to 45 (given)
\n" ); document.write( "Therefore
\n" ); document.write( "x*(4x+3)= 45
\n" ); document.write( "4x^2+3x = 45
\n" ); document.write( "4x^2 + 3x -45=0
\n" ); document.write( "4x^2 + 15x -12x -45=0
\n" ); document.write( "x*(4x+15) -3*(4x+15)=0
\n" ); document.write( "(x-3)(4x+15)=0
\n" ); document.write( "so x=3 or 15/4
\n" ); document.write( "Ans : Length = 15ft and width=3ft
\n" ); document.write( " \n" ); document.write( "

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