document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=738663>Question 738663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> W varies inversely with square of T.<BR>\n" );
document.write( "1) Write the equation that models this relationship.<BR>\n" );
document.write( "2) If W =63 when T is 3, find the value of W( to the nearest 10th) when T is 12.<BR>\n" );
document.write( "***please work out and amswer*** thank you!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450884 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450884\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we know \"W varies inversely with square of T\", so we can write the proportion as\r<BR>\n" );
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document.write( "W = k / (T^2)   where k is the constant of proportionality\r<BR>\n" );
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document.write( "for W=63 when T is 3 we have\r<BR>\n" );
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document.write( "63 = k / 3^2 and k = 63 * 9 = 567\r<BR>\n" );
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document.write( "now when T = 12, we have\r<BR>\n" );
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document.write( "W = 567 / 12 = 47.3\r<BR>\n" );
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