document.write( "Question 64463: To solve systems of equations by the substitution method. My son needs help with these 2 problems:\r
\n" ); document.write( "\n" ); document.write( "(1) x = 3y – 1
\n" ); document.write( " x +2y = 9\r
\n" ); document.write( "\n" ); document.write( "(2) 2x – 3y = 12
\n" ); document.write( " x = 4y +1\r
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Algebra.Com's Answer #45088 by Earlsdon(6294)\"\" \"About 
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Solve by substitution:
\n" ); document.write( "1) \"x+=+3y-1\" Substitute this equation for x into the second equation and solve for y.
\n" ); document.write( "\"x%2B2y+=+9\"\r
\n" ); document.write( "\n" ); document.write( "\"%283y-1%29%2B2y+=+9\" Simplify and solve for y.
\n" ); document.write( "\"3y%2B2y-1+=+9\" Add the y-terms.
\n" ); document.write( "\"5y-1+=+9\" Add 1 to both sides of the equation.
\n" ); document.write( "\"5y+=+10\" Finally, divide both sides by 5.
\n" ); document.write( "\"y+=+2\" Now substitute this value of y into the first equation and solve for x.
\n" ); document.write( "\"x+=+3%282%29-1\"
\n" ); document.write( "\"x+=+6-1\"
\n" ); document.write( "\"x+=+5\"\r
\n" ); document.write( "\n" ); document.write( "The solution is: (5, 2)\r
\n" ); document.write( "\n" ); document.write( "2) \"2x-3y+=+12\"
\n" ); document.write( "\"x+=+4y%2B1\" Substitute this equation for x into the first equation and solve for y.
\n" ); document.write( "\"2%284y%2B1%29-3y+=+12\" Simplify and solve for y.
\n" ); document.write( "\"8y%2B2-3y+=+12\" Combine the y-terms.
\n" ); document.write( "\"5y%2B2+=+12\" Subtract 2 from both sides of the equation.
\n" ); document.write( "\"5y+=+10\" Finally, divide both sides by 5.
\n" ); document.write( "\"y+=+2\" Now substitute this value for y into the second equation and solve for x.
\n" ); document.write( "\"x+=+4%282%29%2B1\"
\n" ); document.write( "\"x+=+8%2B1\"
\n" ); document.write( "\"x+=+9\"
\n" ); document.write( "The solution is: (9, 2)
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