document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=738501>Question 738501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If angle A is acute and tanA is 2/3, them...\r<BR>\n" );
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document.write( "how do you get the answer of cot(90° &#8722; A) =2/3? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450869 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If angle A is acute and tanA is 2/3, them... <BR>\n" );
document.write( "how do you get the answer of cot(90° &#8722; A) =2/3<BR>\n" );
document.write( "Say, you are working a 30-60 right triangle, for example:<BR>\n" );
document.write( "let A=30º<BR>\n" );
document.write( "tan(30º)=1/&#8730;3<BR>\n" );
document.write( "cot (90-30)=cot(60º)=1/&#8730;3<BR>\n" );
document.write( "I used 30º for this example, but it will work for any acute angle.<BR>\n" );
document.write( "This identity also works for sin and cos functions.<BR>\n" );
document.write( "sin 30º=1/2<BR>\n" );
document.write( "cos (90-30)=cos(60º)=1/2 </SPAN>\n" );
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