document.write( "Question 738448: Find the x-intercepts and y-intercepts of the graph of the equation y=x^2 + 8 \n" ); document.write( "

Algebra.Com's Answer #450813 by DrRodion(1) $\"\"$ $\"About$

You can put this solution on YOUR website!
As you should have learned intercepts occur when the line intersects the x or y axis. Think about when a line will intercept the x axis..... When $\"y+=+0\"$ and the same for the y intercept.... When $\"x+=+0\"$ . So what you need to do to find the intercepts in our example is set the x or y value to 0 and solve for the other variable. The equation you gave is $\"y+=+x%5E2+%2B+8\"$ . So first we will set $\"x+=+0\"$ , so the new equation is $\"y+=+0%5E2+%2B+8\"$ . So as we know 0 to any power will always be 0 so if we simplify we get $\"y+=+8\"$ . This means when you x value equals 0 you y value equals 8, this is you y intercept. Then we do the same for x. First we set $\"y+=+0\"$ and then adjust your equation to be $\"0+=+x%5E2+%2B+8\"$ then we simplify... but we run into a problem when we reach $\"+-8+=+x%5E2\"$ , we can not square root negative numbers or we get a imaginary answer. This means that we have no x intercept. So our only intercept is (8, 0) \n" ); document.write( "

\n" );