document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=738443>Question 738443</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you show 10 cent with 3 coins? Explain how you know </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450810 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450810\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No you cannot. Here are all the possible ways to have 3 coins (each coin is less than 10 cents)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "penny, penny, penny = 1+1+1 = 3 cents\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "penny, penny, nickel = 1+1+5 = 7 cents\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "penny, nickel, nickel = 1+5+5 = 11 cents...which is NOT 10 cents since it's over 10 cents\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "nickel, nickel, nickel = 5+5+5 = 15 cents...which is NOT 10 cents since it's over 10 cents\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So this shows us that it's not possible to make 10 cents with exactly 3 coins.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );