document.write( "Question 738376: 10c^2 + 25c – 6c – 15 factor by grouping \n" ); document.write( "
Algebra.Com's Answer #450785 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "\"10c%5E2%2B25c-6c-15\" Start with the given expression\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%2810c%5E2%2B25c%29%2B%28-6c-15%29\" Group the terms in two pairs\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5c%282c%2B5%29-3%282c%2B5%29\" Factor out the GCF \"5c\" out of the first group. Factor out the GCF \"-3\" out of the second group\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%285c-3%29%282c%2B5%29\" Since we have the common term \"2c%2B5\", we can combine like terms\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"10c%5E2%2B25c-6c-15\" factors to \"%285c-3%29%282c%2B5%29\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In other words, \"10c%5E2%2B25c-6c-15=%285c-3%29%282c%2B5%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );