document.write( "Question 738119: Jenny does ironing for a dry cleaner. She is paid $150.00 per month plus .25 per shirt and $1.50 per pair of slacks. Last month she ironed a total of 300 pieces and she made $325.00. How many shirts did she irom? How many slacks did she iron?
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Algebra.Com's Answer #450715 by mananth(16946)\"\" \"About 
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shirts ----------x
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\n" ); document.write( "\n" ); document.write( "x+y=300...........................(1)\r
\n" ); document.write( "\n" ); document.write( "0.25x+1.50y+150=325
\n" ); document.write( "multiply by 100\r
\n" ); document.write( "\n" ); document.write( "25x+150y+15000=32500\r
\n" ); document.write( "\n" ); document.write( "25x+150y=17500....................(2)\r
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\n" ); document.write( "\n" ); document.write( "x= shirts
\n" ); document.write( "y= slacks
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\n" ); document.write( "1 x + 1 y = 300 .............1
\n" ); document.write( "Total value
\n" ); document.write( "25 x + 150 y = 17,500 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -150
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-150 x -150 y = -45,000
\n" ); document.write( "25 x + 150 y = 17,500
\n" ); document.write( "Add the two equations
\n" ); document.write( "-125 x = -27,500
\n" ); document.write( "/ -125
\n" ); document.write( "x = 220
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1 x + 1 y = 300
\n" ); document.write( "220 + y = 300
\n" ); document.write( " y = 300 -220
\n" ); document.write( " y = 80
\n" ); document.write( " y = 80
\n" ); document.write( "x= 220 shirts
\n" ); document.write( "y= 80 slacks
\n" ); document.write( "m.ananth@hotmail.ca
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