document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=738135>Question 738135</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in a triangle, the sum of all angles equals 180 degrees. <BR>\n" );
document.write( "If one angle equals 72 degrees, and then angle X is two times that of angle Y. I know the answer is X = 36 and Y = 72. My question is, how do you get that answer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450710 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Set up two equations.<P><BR>\n" );
document.write( "1:  Angle x is two times angle y:  x=2y<P><BR>\n" );
document.write( "2:  The sum of all angles is 180 degrees: 72 + x + y = 180 so x+y = 180-72 = 108<P><BR>\n" );
document.write( "Substitute 2y for x (as shown in equation 1) in equation 2.  2y+y = 108<P><BR>\n" );
document.write( "3y = 108<P><BR>\n" );
document.write( "y = 36<P><BR>\n" );
document.write( "x = 2y = 2(36) = 72 degrees.  You had it backwards...x is twice angle y.<BR>\n" );
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