document.write( "Question 738139: An investor invested $13000 part a 8% and the rest at 12%. Find the amount invested at each rate if the annual income from the two investments is $1240 \n" ); document.write( "

Algebra.Com's Answer #450700 by mananth(16946) $\"\"$ $\"About$

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Part I 8.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 12.00% per annum ------------ Amount invested = y
\n" ); document.write( " 13000
\n" ); document.write( "Interest----- 1240.00
\n" ); document.write( "
\n" ); document.write( "Part I 8.00% per annum ---x
\n" ); document.write( "Part II 12.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 13000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "8.00% x + 12.00% y= 1240
\n" ); document.write( "Multiply by 100
\n" ); document.write( "8 x + 12 y= 124000.00 --------2
\n" ); document.write( "Multiply (1) by -8
\n" ); document.write( "we get
\n" ); document.write( "-8 x -8 y= -104000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 4 y= 20000
\n" ); document.write( "divide by 4
\n" ); document.write( " y = 5000
\n" ); document.write( "Part I 8.00% $ 8000
\n" ); document.write( "Part II 12.00% $ 5000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "8000 --------- 8.00% ------- 640.00
\n" ); document.write( "5000 ------------- 12.00% ------- 600.00
\n" ); document.write( "Total -------------------- 1240.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

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