document.write( "Question 64449: If logk4=2/3 then k=?\r
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Algebra.Com's Answer #45067 by stanbon(75887) ![]() You can put this solution on YOUR website! If logk4=2/3 then k=? \n" ); document.write( "K^(2/3)=4 \n" ); document.write( "Raise both sides to the 3/2 power to get: \n" ); document.write( "k=4^(3/2) \n" ); document.write( "k=2^3 \n" ); document.write( "k=8 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |