document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=738104>Question 738104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 3 number is 38. The second number is nine more than double the first, and the third number is one less than double the first. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450666 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450666\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of 3 number is 38. The second number is nine more than double the first, and the third number is one less than double the first.<BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "a + b + c = 38<BR>\n" );
document.write( "b = 2a + 9<BR>\n" );
document.write( "c = 2a-1<BR>\n" );
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document.write( "Substitute for \"b\" and for \"c\" and solve for \"a\":<BR>\n" );
document.write( "a + (2a+9)+(2a-1) = 38<BR>\n" );
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document.write( "5a + 8 = 38<BR>\n" );
document.write( "5a = 30<BR>\n" );
document.write( "a = 6<BR>\n" );
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document.write( "b = 2a+9 = 12+9 = 21<BR>\n" );
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document.write( "c = 2a-1 = 12-1 = 11<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================== </SPAN>\n" );
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