document.write( "Question 738012: Find the complement and supplement of an angle with the given measure.\r
\n" ); document.write( "\n" ); document.write( "32°20'\r
\n" ); document.write( "\n" ); document.write( "I got C: 57° 80'
\n" ); document.write( "but it's wrong. Help? \n" ); document.write( "

Algebra.Com's Answer #450639 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!
for angle $\"32\"$ ° $\"20\"$ ' the complement is \r
\n" ); document.write( "\n" ); document.write( " $\"90\"$ °-( $\"32\"$ ° $\"20\"$ ')......take on degree from $\"90\"$ ° and convert in minutes\r
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\n" ); document.write( "\n" ); document.write( "( $\"89\"$ ° $\"60\"$ ')-( $\"32\"$ ° $\"20\"$ ')...now subtract degrees from degrees and minutes from minutes\r
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\n" ); document.write( "\n" ); document.write( "( $\"89\"$ °- $\"32\"$ °)( $\"60\"$ '- $\"20\"$ ')\r
\n" ); document.write( "\n" ); document.write( " $\"57\"$ ° $\"40\"$ '\r
\n" ); document.write( "\n" ); document.write( "supplement\r
\n" ); document.write( "\n" ); document.write( " $\"180\"$ °-( $\"32\"$ ° $\"20\"$ ')......take on degree from $\"180\"$ ° and convert in minutes\r
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\n" ); document.write( "\n" ); document.write( "( $\"179\"$ ° $\"60\"$ ')-( $\"32\"$ ° $\"20\"$ ')...now subtract degrees from degrees and minutes from minutes\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "( $\"179\"$ °- $\"32\"$ °)( $\"60\"$ '- $\"20\"$ ')\r
\n" ); document.write( "\n" ); document.write( " $\"147\"$ ° $\"40\"$ '\r
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