document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=64379>Question 64379</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/093979862x/algebrahomeworkh>An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Help to solve\r<BR>\n" );
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document.write( "3x(2 - 6^0) - 9x = 5x^0 - absolute value of -9 - 6 end absolute vale -2(x-4^0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #45062 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=45062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x(2 - 6^0) - 9x = 5x^0 - /-9 - 6/ -2(x-4^0)<BR>\n" );
document.write( "[any number raised to a zero power equals (1)]<BR>\n" );
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document.write( "3x(2 - (1)) - 9x = 5(1) - /-9 - 6/ -2(x-(1))<BR>\n" );
document.write( "3x(1) - 9x = 5 - /-15/ -2(x-1) [simplify]<BR>\n" );
document.write( "3x - 9x = 5 - (+15) -2x+2)<BR>\n" );
document.write( "-6x = 5 +15 -2x+2<BR>\n" );
document.write( "-6x = 22 -2x<BR>\n" );
document.write( "-6x+2x=22<BR>\n" );
document.write( "-4x=22<BR>\n" );
document.write( "x=-22/4<BR>\n" );
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document.write( "check by plugging x=-22/4 back into the original equation.<BR>\n" );
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