document.write( "Question 737805: suppose you drive 100 mile home for fall break. your return trip took 30 minutes less because you drive 10 mph faster \n" ); document.write( "

Algebra.Com's Answer #450574 by Ed Parker(21) $\"\"$ $\"About$

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suppose you drive 100 mile home for fall break. your return trip took 30 minutes less because you drive 10 mph faster. What was your rate on the return trip?
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document.write( "             distance     rate      time=distance/rate\r\n" );
document.write( "going home     100         x            100/x \r\n" );
document.write( "returning      100        x+10          100/(x+10)\r\n" );
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document.write( "             \r\n" );
document.write( "           hour\r\n" );
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document.write( "                  \r\n" );
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document.write( "Solve that and get x=40 mph going home and therefore the returning rate\r\n" );
document.write( "is x+10 or 40+10 = 50 mph.\r\n" );
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document.write( "Edwin

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