document.write( "Question 737804: suppose you drive 100 mile home for fall break. your return trip took 30 minutes less because you drive 10 mph faster. What was your rate on the return trip? \n" ); document.write( "

Algebra.Com's Answer #450573 by Ed Parker(21) $\"\"$ $\"About$

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suppose you drive 100 mile home for fall break. your return trip took 30 minutes less because you drive 10 mph faster. What was your rate on the return trip?
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document.write( "             distance     rate      time=distance/rate\r\n" );
document.write( "going home     100         x            100/x \r\n" );
document.write( "returning      100        x+10          100/(x+10)\r\n" );
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document.write( "             \r\n" );
document.write( "           hour\r\n" );
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document.write( "                  \r\n" );
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document.write( "Solve that and get x=40 mph going home and therefore the returning rate\r\n" );
document.write( "is x+10 or 40+10 = 50 mph.\r\n" );
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document.write( "Edwin

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