document.write( "Question 737783: How many liters of a 10% saline solution must be mixed with 20 liters of a 15% saline solution to make a 12% saline solution? \n" ); document.write( "

Algebra.Com's Answer #450562 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+x+\"$ = liters of 10% solution needed
\n" ); document.write( " $\"+.1x+\"$ = liters of salt in 10% solution
\n" ); document.write( " $\"+.15%2A20+=+3+\"$ liters of salt in 15% solution
\n" ); document.write( "-------------------
\n" ); document.write( " $\"+%28+.1x+%2B+3+%29+%2F+%28+x+%2B+20+%29+=+.12+\"$
\n" ); document.write( " $\"+.1x+%2B+3+=+.12%2A%28+x+%2B+20+%29+\"$
\n" ); document.write( " $\"+.1x+%2B+3+=+.12x+%2B+2.4+\"$
\n" ); document.write( " $\"+.02x+=+.6+\"$
\n" ); document.write( " $\"+x+=+30+\"$
\n" ); document.write( "30 liters of 10% solution are needed
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+.1x+%2B+3+%29+%2F+%28+x+%2B+20+%29+=+.12+\"$
\n" ); document.write( " $\"+%28+.1%2A30+%2B+3+%29+%2F+%28+30+%2B+20+%29+=+.12+\"$
\n" ); document.write( " $\"+%28+3%2B+3+%29+%2F+50+=+.12+\"$
\n" ); document.write( " $\"+6+=+.12%2A50+\"$
\n" ); document.write( " $\"+6+=+6+\"$
\n" ); document.write( "OK \n" ); document.write( "

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