document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=737642>Question 737642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 4 different math books, 6 different physics books and 2 different chemistry books are to be arranged on a shelf. How many different arrangements are possible if\r<BR>\n" );
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document.write( " a) The books in each particular subject must all stand together<BR>\n" );
document.write( " b) Only the math books must stand together  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #450561 by </B><A HREF=/tutors/aboutme.mpl?userid=Susan-math><B>Susan-math(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Susan-math><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=450561\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) First choose the order of the books subjects: 3 subjects so 3! Then arrange each subject: 4!6!2! So all together: 3!4!6!2!=207,360\r<BR>\n" );
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document.write( "2) First arrange the math books. there are 4! ways to do this. since they have to stay this way - together - consider the math subject now as 1 big \"book\", 6 physics boos and 2 chemistry books.\r<BR>\n" );
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document.write( "Then we have 1+6+2=9 \"books\" and can arrange them 9! ways. \r<BR>\n" );
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document.write( "So we can have 4!9!=8,709,120 arrangements.  </SPAN>\n" );
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