document.write( "Question 735356: Using log 4 and log 12, evaluate log 1/12 \n" ); document.write( "
Algebra.Com's Answer #450543 by Susan-math(40)\"\" \"About 
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\"log%281%2F12%29=log1-log12\"\r
\n" ); document.write( "\n" ); document.write( "recall that \"log1=0\" since \"10%5E0=1\"\r
\n" ); document.write( "\n" ); document.write( "so \"log%281%2F12%29=log1-log12=0-log12=-log12\"
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