document.write( "Question 735078: log3x=log4+log(x-1)
\n" ); document.write( "solve this logarithmic equation \n" ); document.write( "

Algebra.Com's Answer #450542 by Susan-math(40) $\"\"$ $\"About$

You can put this solution on YOUR website!
Use the rule\r
\n" ); document.write( "\n" ); document.write( " $\"loga%2Blogb=log%28ab%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"log4%2Blog%28x-1%29=log%284%28x-1%29%29\"$ \r
\n" ); document.write( "\n" ); document.write( "so $\"log%283x%29=log%284%28x-1%29%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3x=4%28x-1%29\"$
\n" ); document.write( " $\"3x=4x-4\"$
\n" ); document.write( " $\"-x=-4\"$
\n" ); document.write( " $\"x=4\"$
\n" ); document.write( " \n" ); document.write( "

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