document.write( "Question 735036: log (base3) x = 1/2 log (base3) 25 - 5 log (base3) 2 \n" ); document.write( "
Algebra.Com's Answer #450540 by Susan-math(40)\"\" \"About 
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For simplicity of typing I am leaving the base off the logs.\r
\n" ); document.write( "\n" ); document.write( "Use the log rules:\r
\n" ); document.write( "\n" ); document.write( "first: \"rloga=log%28a%5Er%29\"\r
\n" ); document.write( "\n" ); document.write( "so \"%281%2F2%29log+25=log%2825%5E%281%2F2%29%29=log%28sqrt%2825%29%29=log5\"
\n" ); document.write( "and \"5log2=log%282%5E5%29=log32\"\r
\n" ); document.write( "\n" ); document.write( "Now use the rule: \"loga-logb=log%28a%2Fb%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log5-log32=log%285%2F32%29\"\r
\n" ); document.write( "\n" ); document.write( "so \r
\n" ); document.write( "\n" ); document.write( "so \"logx=log%285%2F32%29\"\r
\n" ); document.write( "\n" ); document.write( "and \"x=5%2F32\"
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