document.write( "Question 737715: Find all solutions in the interval [0,2pi): 2sin^2(x)=sinx \n" ); document.write( "
Algebra.Com's Answer #450515 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 2sin^2(x)=sinx\r \n" ); document.write( "\n" ); document.write( "2sin^2(x)-sinx=0\r \n" ); document.write( "\n" ); document.write( "sinx(2sinx-1)=0\r \n" ); document.write( "\n" ); document.write( "either sin x = 0 OR 2sinx-1=0\r \n" ); document.write( "\n" ); document.write( "2sinx-1=0 \n" ); document.write( "sinx=1/2\r \n" ); document.write( "\n" ); document.write( "sinx = 1/2 for pi/6 radians and co terminal of pi/6\r \n" ); document.write( "\n" ); document.write( "x=0,pi/6,5pi/6\r \n" ); document.write( "\n" ); document.write( "pi not included\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |