document.write( "Question 737601: This is a test preparation question but I just am not sure how to solve it or where to start:\r
\n" ); document.write( "\n" ); document.write( "If sin t = 1/3 and pi/2 < t < pi, then determine the exact value of cos t, sin(2pi - t), and cos(2pi - t).\r
\n" ); document.write( "\n" ); document.write( "the answer is \"-2sqrt%282%29%2F3\",\"+-1%2F3\",\"+-2sqrt%282%29%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Thank you in advance!
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Algebra.Com's Answer #450503 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
If sin t = 1/3 and pi/2 < t < pi, then determine the exact value of cos t, sin(2pi - t), and cos(2pi - t).
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\n" ); document.write( "let O=opposite side
\n" ); document.write( "let A=adjacent side
\n" ); document.write( "let H=hypotenuse
\n" ); document.write( "...
\n" ); document.write( "sin t=1/3=O/H
\n" ); document.write( "O=1, H=3
\n" ); document.write( "\"A=sqrt%28H%5E2-1%5E2%29=sqrt%289-1%29=-sqrt%288%29\"
\n" ); document.write( "\"cos%28t%29=A%2FH=-sqrt%288%29%2F3=-2sqrt%282%29%2F3\"
\n" ); document.write( "...
\n" ); document.write( "\"sin%282pi-t%29=-1%2F3\" (Note: this moves the standard position of t from Q2 to Q3 where sin<0, with the same reference angle) You could use the sin addition formula to show this.
\n" ); document.write( "...
\n" ); document.write( "\"cos%282pi-t%29=-2sqrt%282%29%2F3\"(Note: this moves the standard position of t from Q2 to Q3 where cos<0, with the same reference angle) You could use the cos addition formula to show this.
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